A child sitting 1.80 m from the center of a merry-go-round moves with a speed of 1.45 m/s . Calculate the centripetal acceleration of the child.Calculate the net horizontal force exerted on the child. (mass = 28.5 kg )

physics 8 éme

acceleration=v^2/r=1.45^2/1.80 m/s^2

To calculate the centripetal acceleration of the child, we can use the formula:

centripetal acceleration (a) = (velocity (v))^2 / radius (r)

Given:
Velocity (v) = 1.45 m/s
Radius (r) = 1.80 m

Substituting the given values into the formula, we can find the centripetal acceleration:

a = (1.45 m/s)^2 / 1.80 m
a ≈ 1.177 m/s^2

Therefore, the centripetal acceleration of the child is approximately 1.177 m/s^2.

To calculate the net horizontal force exerted on the child, we can use the formula:

Force (F) = mass (m) × acceleration (a)

Given:
Mass (m) = 28.5 kg
Acceleration (a) = centripetal acceleration (1.177 m/s^2)

Substituting the given values into the formula, we can find the net horizontal force:

F = 28.5 kg × 1.177 m/s^2
F ≈ 33.6265 N

Therefore, the net horizontal force exerted on the child is approximately 33.63 N.