A child sitting 1.80 m from the center of a merry-go-round moves with a speed of 1.45 m/s . Calculate the centripetal acceleration of the child.Calculate the net horizontal force exerted on the child. (mass = 28.5 kg )
physics 8 éme
acceleration=v^2/r=1.45^2/1.80 m/s^2
To calculate the centripetal acceleration of the child, we can use the formula:
centripetal acceleration (a) = (velocity (v))^2 / radius (r)
Given:
Velocity (v) = 1.45 m/s
Radius (r) = 1.80 m
Substituting the given values into the formula, we can find the centripetal acceleration:
a = (1.45 m/s)^2 / 1.80 m
a ≈ 1.177 m/s^2
Therefore, the centripetal acceleration of the child is approximately 1.177 m/s^2.
To calculate the net horizontal force exerted on the child, we can use the formula:
Force (F) = mass (m) × acceleration (a)
Given:
Mass (m) = 28.5 kg
Acceleration (a) = centripetal acceleration (1.177 m/s^2)
Substituting the given values into the formula, we can find the net horizontal force:
F = 28.5 kg × 1.177 m/s^2
F ≈ 33.6265 N
Therefore, the net horizontal force exerted on the child is approximately 33.63 N.