The first term of an AP is equal to thrice the common difference. What is the sixth term of the AP,if the common difference is 8
a = 3d
d = 8
a = 3(8)
a = 24
Therefore, the sixth term will be:
Tn = a+(n-1)d
a=24; d=8; n=6
T6 = 24+(6-1)8
T6 = 24+(5)8
T6 = 24+(5x8)
T6 = 24+40
T6 = 64
a = 3d
d = 8
so, a=24 and the AP is
24,32,40,...
from sir steve work
remeber that 6th term is
6th term=a+5d
=24+5*8
=64
Well, in this case, the first term is equal to three times the common difference, which means it's 3 * 8 = 24. So, let's find the sixth term using this information.
To do that, we can use the formula for the nth term of an arithmetic progression:
nth term = first term + (n - 1) * common difference
Plugging in the values we already know, we have:
sixth term = 24 + (6 - 1) * 8
sixth term = 24 + 5 * 8
sixth term = 24 + 40
sixth term = 64
So, the sixth term of the arithmetic progression is 64. Now, isn't that arithmetically satisfying?
To find the sixth term of an Arithmetic Progression (AP), we need to know the first term, common difference, and the formula for the nth term of an AP.
Given:
First term (a) = 3 times the common difference (d)
Common difference (d) = 8
Let's calculate the value of the first term (a):
a = 3d
a = 3 * 8
a = 24
Now, we know the first term (a) is 24, and the common difference (d) is 8.
The formula for the nth term of an AP is given by:
an = a + (n - 1)d
Substituting the values, we can find the sixth term (a6):
a6 = a + (6 - 1)d
a6 = 24 + (6 - 1) * 8
a6 = 24 + 5 * 8
a6 = 24 + 40
a6 = 64
Therefore, the sixth term of the AP is 64.