A swimmer can swim a distance of 36 kilometer in the direction of water current in the same time, which he require to swim 36 kilometer in the opposite direction of water current in stream. If in still water, swimmer has speed of 12 kilometer per hour more than the speed of that of water in stream, then what is the speed of water?

To solve this problem, let's break it down step by step:

Let's assume the swimmer's speed in still water is "S" kilometers per hour, and the speed of the water current is "W" kilometers per hour.

1. A swimmer can swim a distance of 36 kilometers in the direction of the water current in the same time it takes to swim 36 kilometers in the opposite direction.

This means that the swimmer's effective speed with the current is equal to their effective speed against the current. Let's calculate the effective speed of the swimmer in both cases:

Effective speed with the current = S + W
Effective speed against the current = S - W

Since the swimmer takes the same time to swim 36 kilometers in both scenarios, we can equate the two effective speeds:

S + W = S - W

2W = 0
W = 0

From this equation, we can conclude that the speed of the water current is 0 kilometers per hour. However, this is not a practical scenario since there is always some water current. Therefore, there seems to be an error in the given information or the problem itself. Please double-check the question or provide additional details if available.