0.717g of potassium dihydrogen phosphate in 500ml concentration in ppm
0.717 g KH2PO4 in 500 mL to ppm.
You want to convert to mg/L.
717 mg/500 mL = 1434 mg/L = 1434 ppm.
To calculate the concentration of potassium dihydrogen phosphate (KH2PO4) in parts per million (ppm), follow these steps:
Step 1: Convert grams to milligrams
Multiply the given mass of KH2PO4 (0.717g) by 1000 to convert it to milligrams:
0.717g x 1000 = 717mg
Step 2: Calculate the concentration in milligrams per liter (mg/L)
To obtain the concentration in mg/L, divide the mass in milligrams (717mg) by the volume in liters (500mL converted to 0.5L):
717mg / 0.5L = 1434 mg/L
Step 3: Convert mg/L to ppm
1 ppm is equal to 1 mg/L, so the concentration in mg/L (1434 mg/L) is also equivalent to 1434 ppm.
Therefore, the concentration of potassium dihydrogen phosphate in 500mL is 1434 ppm.
To find the concentration of potassium dihydrogen phosphate in parts per million (ppm), we need to know the molar mass of potassium dihydrogen phosphate and the mass of the compound present in the given volume.
1. Calculate the molar mass of potassium dihydrogen phosphate (KH2PO4).
- Potassium (K) has a molar mass of 39.10 g/mol.
- Hydrogen (H) has a molar mass of 1.01 g/mol.
- Phosphorus (P) has a molar mass of 30.97 g/mol.
- Oxygen (O) has a molar mass of 16.00 g/mol.
The molar mass of KH2PO4 is: (39.10) + (2 * 1.01) + (30.97) + (4 * 16.00) = 136.09 g/mol.
2. Calculate the mass of potassium dihydrogen phosphate in grams.
Given that the amount is 0.717 g.
3. Convert the volume from milliliters (mL) to liters (L).
500 mL = 0.5 L.
4. Calculate the concentration in ppm.
ppm (parts per million) is defined as the number of parts of solute per one million parts of solution.
The formula for ppm concentration is: (mass of solute / volume of solution) * 10^6.
Concentration (ppm) = (0.717 g / 0.5 L) * 10^6 = 1434 ppm.
Therefore, the concentration of potassium dihydrogen phosphate in the given solution is 1434 ppm.