8.f2 ∙ f4
A. (2f)^8
B. (2f)^6
C. F^8
D. F^6
10.X^11/x^4
A. X^7
B. X^15
C. X^44
D.x 11/4
just normal indices rule
a^b/a^a=a^(b-a)
with that hint
play around with your question
I'm not sure
125 · 5=?
can,t you do normal multiplication?
you should be able to do that
Yay I can
or you mean
since
a^b.a^a=a^b+a
then
5^3.5^1=?
first of all get your notation straight. Use ^ for exponents. Second follow the rule that Collins gave you (sort of):
a^b/a^c=a^(b-c)
and
a^b a^c = a^(b+c)
f^8..easy
To simplify the expression 8.f2 ∙ f4, we need to multiply the coefficients and combine the variables.
The coefficient of the first term is 8, and the coefficient of the second term is 1.
To multiply the coefficients, we multiply 8 and 1, which gives us 8.
For the variables, we need to multiply the variables with the same base, f. In this case, we have f^2 and f^4.
When multiplying variables with the same base, we add their exponents. So, f^2 ∙ f^4 is equal to f^(2+4), which simplifies to f^6.
Putting it all together, the result of 8.f2 ∙ f4 is 8f^6.
Therefore, the correct option is: B. (2f)^6.