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If three successive coefficients in the expansion of (1+x)n are 210,120 and 45 respectively, find n.
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10
Look at a table of binomial coefficients
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In the expansion of (2x^2 + a/x)^6, the coefficients of x^6 and x^3 are equal. Find the value of the non-zero constant a and the
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In the expansion, oobleck gave you the terms containing x^6 and x^3, namely 160a^3x^3 and 240a^2x^6
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in the binomial expansion of (1+x/k)^n, where k is a constant and n is a positive integer, the coefficients of x and x^2 are
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(1+x/k)^n = 1^n + n(x/k) + n(n-1)/2 (x/k)^2 n/k = n(n-1)/2k^2 2kn/2k^2 = n(n-1)/2k^2 2kn = n(n-1) 2k
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the two terms are C(9,2) 3^7 (kx)^2, C(9,3) 3^6 (kx)^3 so the coefficients are 78732 k^2, 61236 k^3
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1. Which equation correctly shows beta decay?
(A) 210/82 Pb -> 209/81 Tl + 0/-1 e + y (B) 210/82 Pb -> 209/83 Bi + 0/-1 e + y (C)
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(E) 210/82Pb-> 210/83Bi + 0/-1e +Y (A) 12.4 grams
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A consultant charges $30 for each hour she works on a consultation, plus a flat $45 consulting fee. Which equation could be used
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45h + 30 = 210
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A consultant charges $45 for each hour she works on a consultation, plus a flat $30 consulting fee. Which equation could be used
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#10.
A consultant charges $30 for each hour she works on a consultation, plus a flat $45 consulting fee. Which equation could be
Top answer:
45h + 30 = 210
Read more.
A consultant charges $45 for each hour she works on a consultation, plus a flat $30 consulting fee. Which equation could be used
Top answer:
45h + 30 = 210
Read more.
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