what is the exterior angle sum of a 500 gon?
I got .72 but I'm not sure if this is right, help would be very grateful :)
the exterior angles always sum to 360.
the 360 answer is right.
To find the sum of the exterior angles of a polygon, you can use the formula:
Sum of exterior angles = 360°
In a polygon with n sides (n-gon), each exterior angle is 360° divided by n.
For a 500-gon, the sum of the exterior angles would be:
Sum of exterior angles = 360° / 500
Simplifying this gives:
Sum of exterior angles = 0.72°
So your calculation of 0.72° is correct. The sum of the exterior angles of a 500-gon is indeed 0.72°.
To find the exterior angle sum of a polygon, you can use the formula:
Exterior angle sum = 360°
In a regular polygon, the exterior angles are all equal, so you can divide the exterior angle sum by the number of sides to find the measure of each exterior angle.
For a 500-gon, the exterior angle sum would be:
Exterior angle sum = 360°
Each exterior angle of a regular polygon with n sides can be found using the formula:
Each exterior angle = Exterior angle sum / n
So, for a 500-gon, the measure of each exterior angle would be:
Each exterior angle = 360° / 500
Simplifying this expression:
Each exterior angle = 0.72°
Therefore, the measure of each exterior angle of a 500-gon is 0.72 degrees, which is what you obtained. Your answer of 0.72 is correct!
Keep in mind that while the measure of each exterior angle of a 500-gon is indeed 0.72 degrees, the term "exterior angle sum" refers to the sum of all the exterior angles, which is always 360 degrees for any polygon.