assuming that sea water is an aqueous solution of NaCl its density is 1.025g/mL at 20C temperature and NaCl concentration is 3.5%(by mass), the normality of the sea water?

To calculate the normality of a solution, we need to have information about the molarity and the number of equivalents of the solute.

Normality (N) is defined as the number of equivalents of a solute per liter of solution. It is different from molarity (M), which is the number of moles of solute per liter of solution.

In this case, we have the concentration of NaCl in terms of percentage by mass, but we need to convert it to molarity first.

Step 1: Convert percentage by mass to molarity.

Given:
- NaCl concentration: 3.5% (by mass)
- Density of sea water: 1.025 g/mL

First, we need to calculate the mass of NaCl in 1 liter of sea water.

Mass of NaCl in 1 liter of sea water = (3.5 g/100 mL) * (1000 mL/1 L) = 35 g/L

Since we know the density of sea water is 1.025 g/mL, we can calculate the mass of 1 liter of sea water.

Mass of 1 liter of sea water = 1.025 g/mL * 1000 mL = 1025 g/L

Now, we can determine the molarity of NaCl in the sea water.

Molarity (M) = moles of solute / volume of solution (in liters)

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

The molar mass of NaCl is 58.44 g/mol.

Moles of NaCl = 35 g / 58.44 g/mol = 0.599 mol

Volume of solution = 1 L

Molarity (M) = 0.599 mol / 1 L = 0.599 M

Step 2: Calculate normality using the molarity and the number of equivalents.

The normality (N) is given by the equation N = M * equivalents.

For NaCl, as it is a strong electrolyte, it dissociates into Na+ and Cl- ions. Each Na+ or Cl- ion contributes one equivalent to the solution.

Since NaCl is a salt and completely dissociates in water,
Number of equivalents = Number of moles of NaCl

Number of equivalents = 0.599 mol

Normality (N) = Molarity * Number of equivalents
Normality (N) = 0.599 M * 0.599 mol = 0.359 N

Therefore, the normality of the sea water containing 3.5% (by mass) NaCl is approximately 0.359 N.

To find the normality of a solution, we need to know the molarity of the solute.

1. Start by calculating the molarity of the NaCl solution using mass percent concentration:
Mass percent (by mass) = (mass of solute / mass of solution) × 100
3.5 = (mass of NaCl / mass of solution) × 100

Since the density of the solution is given, we can calculate the mass of the solution.
1.025 g/mL = mass of solution / volume of solution
mass of solution = 1.025 g/mL × volume of solution

Substituting the equation above into the mass percent equation:
3.5 = (mass of NaCl / (1.025 g/mL × volume of solution) ) × 100

Now, we need to convert mass percent to grams:
mass of NaCl = 3.5 g × (volume of solution / 100)

Next, we need to calculate the molar mass of NaCl:
Molar mass of NaCl = atomic weight of Na + atomic weight of Cl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

Now, we can calculate the molarity of the NaCl solution:
Molarity = (mass of NaCl / molar mass of NaCl) / volume of solution)

Finally, we can calculate the normality of the solution:
Normality = Molarity × n
Here, n is the number of equivalents of the solute in the balanced chemical equation. For NaCl, since it dissociates into one Na+ ion and one Cl- ion, n = 1.

So the normality of the sea water can be calculated using the steps above.

Ok, take on liter. It mass is then 1025 grams, so it has salt in the mass amount of .03*1025. Then the moles of sale is that mass divided by 58.44.

Molarity=normality=molesSalt/1