Please Please HELP!!!! I need the answer to this and i've worked it out but I don't know if it is correct... Please check my answer!!!!
The polygons are regular polygons. Find the area of the shaded region to the nearest tenth.
I can't post a picture of it but it shows a larger square with a smaller square inside it at the middle, and it shows the radius of the larger square to be 9 cm and the radius of the small square to be 4 cm. The smaller square is no shaded inside the larger square and you are supposed to the find the shaded region which is the area of the smaller square minus the area of the larger square. Also the area of the larger square includes the area of the small square.
I REALLY hope that was clear enough....
The answer i got was 130 cm^2.... PLEASE HELP!! THANK YOU!!
A1 = (2*9)^2 = 324 cm^2 = Area of larger sq.
A2 = (2*4)^2 = 64 cm^2 = Area of smaller sq.
A2 + As = A1, 64 + As = 324, As = 260 cm^2 = Shaded area.
To find the area of the shaded region, we need to subtract the area of the larger square from the area of the smaller square.
The formula for the area of a square is A = s^2, where "A" is the area and "s" is the length of a side.
First, let's find the area of the larger square. Since the radius of the larger square is 9 cm, the length of a side can be found by multiplying the radius by 2 (since a square has all sides equal in length). Therefore, the length of a side of the larger square is 9 cm * 2 = 18 cm. Thus, the area of the larger square is A = 18 cm * 18 cm = 324 cm^2.
Now, let's find the area of the smaller square. The radius of the smaller square is given as 4 cm, so the length of a side of the smaller square is 4 cm * 2 = 8 cm. Therefore, the area of the smaller square is A = 8 cm * 8 cm = 64 cm^2.
Finally, we can find the area of the shaded region by subtracting the area of the larger square from the area of the smaller square: 64 cm^2 - 324 cm^2 = -260 cm^2.
The result you obtained of 130 cm^2 is not correct. Please double-check your calculations, as there seems to be an error in your method.