calculate weight by volume for 0.8molal urea,density of solution is 1.14gram per ml
To calculate the weight by volume for a 0.8molal urea solution, we need to know the density of the solution. Given that the density of the solution is 1.14 grams per milliliter (g/mL), we can proceed with the calculation.
First, let's define what "0.8 molal" means. A molal solution refers to the number of moles of solute (in this case, urea) dissolved in 1 kilogram of the solvent (water). Therefore, in 1 kilogram of the urea solution, there are 0.8 moles of urea.
Now, we need to find the weight of urea in grams in 1 kilogram of solution:
Weight of urea = Number of moles of urea × Molar mass of urea
The molar mass of urea (CH₄N₂O) is approximately 60.06 grams/mole.
Weight of urea = 0.8 moles × 60.06 grams/mole
Weight of urea = 48.05 grams
Next, we need to find the volume of the solution in milliliters.
Density = Mass/Volume
Volume = Mass/Density
Volume = 1000 grams/1.14 grams/mL
Volume = 877.19 mL
Therefore, in a 0.8molal urea solution with a density of 1.14 g/mL, the weight of the solution is 48.05 grams and the volume is 877.19 mL.