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A torch bulb is marked with 2.4 volts and 0.75 A calculate the power dissipated
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P = i V = .75 * 2.4 = 1.8 Watts
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Four identical bulbs are set up in a series circuit with an 8V battery. The voltage across each bulb is
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B 2 (8 ÷ 4) volts.
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Any response to help would be appreciated
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What is the power dissipated by resistor R1 of the following circuit: two batteries in series (with values V1 = 20 volts and V2
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I = 40V/40,000 ohms = 10^-3 A goes through each resistor, since they are in series. The power
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12 volts is applied across a 4 ohm resistor. How much power is dissipated by the resistor?
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P = E^2/R = 144/4 = 36 W
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10 volts
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The power dissipated is I^2*R = (.05^2)(10) = 0.025 W That is pretty feeble for a light bulb. The
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