A charged capacitor AB carries on its plate A a charge Q=-1.2mC

What is the charge carried by plate B.
Is the voltage U(AB)=V(A)-V(B) positive or negative,
The plates A and B are connected to the terminals of a resistance R: the capacitor gets discharged.
What are the charge carriers which move in the connection wires. What is the direction of the transitional electric current.

THANKS IN ADVANCE.

a) equal and opposite

b) put in the numbers and see
c) only electrons ever move
d) from negative to positive

To find the charge carried by plate B, we need to understand how a capacitor works. A capacitor consists of two plates separated by an insulating material, and when the plates are connected to a power source, one plate becomes positively charged (A) and the other becomes negatively charged (B).

In this case, plate A carries a charge of Q = -1.2 mC. Since the charge on the capacitor is conserved, plate B must carry an equal but opposite charge. Therefore, the charge carried by plate B is also Q = 1.2 mC.

Now, let's consider the voltage U(AB) between the two plates. The voltage difference between two points is defined as the electric potential difference or voltage. In this case, U(AB) represents the voltage between plates A and B.

If V(A) is the potential at plate A and V(B) is the potential at plate B, then U(AB) can be calculated by subtracting V(B) from V(A). Mathematically, U(AB) = V(A) - V(B).

Since plate A is negatively charged, it has a lower potential than plate B. Therefore, V(A) < V(B). As a result, the voltage U(AB) will be negative because the potential at B is greater than the potential at A.

Next, when plates A and B are connected to the terminals of a resistance R and the capacitor gets discharged, the charge carriers that move in the connection wires are electrons. In most conductors, electrons are the primary charge carriers. When an electric current flows, electrons move from the negative terminal to the positive terminal of the power source.

As a result, the transitional electric current in this situation would flow from plate B (negative terminal) through the wires to plate A (positive terminal). The direction of the electric current is opposite to the movement of electrons, so it would flow from plate A to plate B.

In summary:
- The charge carried by plate B is Q = 1.2 mC (equal in magnitude but opposite in sign to the charge on plate A).
- The voltage U(AB) = V(A) - V(B) is negative because the potential at B is greater than the potential at A.
- The charge carriers in the connection wires are electrons.
- The transitional electric current flows from plate A to plate B.