A falling 50-kg skydiver experiences an upward acceleration of 6.2 m/s2 when she opens her parachute. Show (by calculation) how much drag force is produced by the parachute.

How would I calculate this?

I am not certain if you mean just the upward acceleration component of net force, or if you mean she had a net upward acceleration (unusual when falling).

Assuming just the upward component..
F=ma=50*6.2 N

I did this in a previous post. I said Fdrag - mg = ma

Not really sure which they're asking for.

To calculate the drag force produced by the parachute, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the force is the drag force, the mass is the mass of the skydiver, and the acceleration is the upward acceleration experienced when the parachute opens.

The formula for force is given by:

Force = Mass × Acceleration

Given:
Mass of the skydiver (m) = 50 kg
Acceleration (a) = 6.2 m/s²

Substituting the given values into the formula, we get:

Force = 50 kg × 6.2 m/s²

Calculating this, we find:

Force = 310 N

Therefore, the drag force produced by the parachute is 310 Newtons.