Each of two urns contains green balls and red balls. Urn 1 contains 8 green balls and 12 red balls. Urn 2 contains 5 green balls and 8 red balls. If a ball is drawn from each urn, what is P(red and red)?

a. 79/65
b. 24/65
c. 20/33
d. 2/13

Please explain! THANK YOU

pr(r,r)=12/20*8/13

What's the answer Mr. President???

24/65

I have no idea.

I think it is 24/65

To find the probability of drawing a red ball from each urn, we need to calculate the probability of drawing a red ball from each urn separately, and then multiply those probabilities together.

The probability of drawing a red ball from Urn 1 is given by the ratio of the number of red balls to the total number of balls in the urn:

P(red from Urn 1) = 12 / (8 + 12) = 12 / 20 = 3/5

Likewise, the probability of drawing a red ball from Urn 2 is:

P(red from Urn 2) = 8 / (5 + 8) = 8 / 13

Now, we can calculate the probability of drawing a red ball from each urn by multiplying their probabilities together:

P(red and red) = P(red from Urn 1) * P(red from Urn 2) = (3/5) * (8/13)

To simplify this expression, we multiply the numerators and denominators together:

P(red and red) = (3 * 8) / (5 * 13) = 24 / 65

Therefore, the answer is option b. 24/65.