How do I solve this?
The perimeter of a rectangular writing pad is 28 inches. The length is 1 inch
less than twice the width. Find the width.
Show all work!
Translate your English into Math
<The length is 1 inch
less than twice the width>
or L = 2W - 1
<Perimeter is 28 inches>
2L + 2W = 28
2(2W-1) + 2L = 28
I am sure you can solve this
I am just beginning to learn this stuff.
The answer is 7 right?
no
starting from 2(2W-1) + 2L = 28
4w - 2 + 2L = 28
6W = 28+2
6W=30
W = 5 the L = 2W-1
= 10-1
= 9
check 2(9) + 2(5) = 28
Are you sure? I have 4 choices on my
assignment to mark and 9 isn't on there.
The choices are:
A. 8 inches
B. 7 inches
C. 6 inches
D. 5 inches
Yes I am sure.
My answers were W=5 L=9
notice i had verified my answer.
The original equation should be:
2(2w-1)+ 2w = 28 (It used L in the first equation, but L was replaced by 2w-1)
Distribute first:
4w-2 + 2w = 28
Combine like terms:
6w - 2 = 28
Solve:
6w = 30
w = 5
The correct answer is D. Double check it in the original equation.
To solve this problem, we start by translating the given information into mathematical equations. We are told that the length of the writing pad is 1 inch less than twice the width. We can represent this relationship as L = 2W - 1, where L represents the length and W represents the width.
Next, we are given that the perimeter of the writing pad is 28 inches. The formula for the perimeter of a rectangle is 2L + 2W, so we can set up the equation 2L + 2W = 28.
Now, we have a system of equations:
L = 2W - 1
2L + 2W = 28
To solve this system, we can substitute the expression for L from the first equation into the second equation. This gives us 2(2W - 1) + 2W = 28.
Now, we simplify and solve for W:
4W - 2 + 2W = 28
6W - 2 = 28
6W = 30
W = 5
So, the width of the writing pad is 5 inches.
To find the length, we substitute the value of W back into the first equation:
L = 2(5) - 1
L = 10 - 1
L = 9
The length of the writing pad is 9 inches.
Therefore, the correct answer is D. 5 inches.