Carly and rob combined their Pokémon together. Now they have 42 Pokémon altogether. Carly had 4 more Pokémon than rob. How many Pokémon did Carly have?
If Carly had c, the Rob had c-4. So,
c + c-4 = 42
2c = 46
c = 23
So, Carly had 23 and Rob had 19
Did you know that in terms of human male and female pokem-
I agree with Steve.
To find out how many Pokémon Carly had, we can set up a system of equations based on the given information.
Let's assume that Carly had x Pokémon, and Rob had y Pokémon.
According to the problem, the total number of Pokémon they have together is 42:
x + y = 42 ------ (Equation 1)
It is also given that Carly had 4 more Pokémon than Rob:
x = y + 4 ------ (Equation 2)
We can solve this system of equations to find the value of x.
First, let's substitute the value of x from Equation 2 into Equation 1:
(y + 4) + y = 42
2y + 4 = 42
Next, let's isolate the variable y:
2y = 42 - 4
2y = 38
Divide both sides of the equation by 2:
y = 38 / 2
y = 19
Now, substitute the value of y back into Equation 2 to find the value of x:
x = y + 4
x = 19 + 4
x = 23
Therefore, Carly had 23 Pokémon.