Calculus Help Stuck Part 2?
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Calculus Answer Confirming Not Sure Im Right Help?
Evaluate the lim a. lim x> 64 (cube root x4/x64) (∛x4)/(x64) > 0/0 so then let cube root x = u u4/u^364 u4/u^364 = u4/u4(u^2+4u+16) the u4 cancel each other out leaving lim x>64 = 1/u^2+4u+16 1/64^2+4(64)=16 oddly
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i need some serious help with limits in precalc. here are a few questions that i really do not understand. 1. Evaluate: lim (3x^32x^2+5) x> 1 2. Evaluate: lim [ln(4x+1) x>2 3. Evaluate: lim[cos(pi x/3)] x>2 4. Evaluate:
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I have to evaluate the limit of these problems and I can't figure them out! 1.) Lim x> 1 x^2+x2/x^2x 2.) (please note that the 2 is not under the square root) Lim x>0 sqroot 4+h 2/ h
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asked by Jane on December 7, 2014