1.)if an object is dropped from a height of 144 ft the function h(t)=-16t^2+144 gives the height of the object after t seconds. when will the object hit the ground?
a.)1.5 seconds
b.)3 seconds ***
c.) 6 seconds
d.)9 seconds
2.) the area of a play ground is 64 square yards. the length of the play ground is 4 times longer than its width. find the length and the width of the play ground.
a.) L=16 yards; w=4 yards ***
b.)L=2 yards ; w= 32 yards
c.) L=32 yards ; w=2 yards
d.) L=4 yards ; w=16 yards
The first one is tight I dunno about the second 1. B
Would this be 3 seconds???
3 s
Yes, that is correct. The object will hit the ground after 3 seconds.
1.) b.) 3 seconds
Why did the object decide to hit the ground after 3 seconds? Because it was tired of being at such a height and wanted to get closer to the floor for a change of scenery!
2.) a.) L=16 yards; w=4 yards
The playground wanted to have a long and meaningful relationship, so it decided to make its length four times longer than its width. It believes that a strong foundation is the key to a successful relationship!
1.) To find when the object will hit the ground, we need to set the height function h(t) equal to 0, since the object is on the ground when its height is 0.
h(t) = -16t^2 + 144 = 0
Now we can solve this quadratic equation for t. We can divide both sides by -16 to simplify the equation:
t^2 - 9 = 0
To solve this equation, we can use factoring or the quadratic formula. In this case, factoring is the simpler method:
(t - 3)(t + 3) = 0
Setting each factor equal to 0:
t - 3 = 0 or t + 3 = 0
Solving for t:
t = 3 or t = -3
Since time cannot be negative in this case, we discard the solution t = -3. Therefore, the object will hit the ground after 3 seconds. So the correct answer is b.) 3 seconds.
2.) Let's assume the width of the play ground is represented by w yards. The length of the play ground is given as 4 times longer than its width, so we can express the length as 4w yards.
The area of a rectangle is calculated by multiplying the length and the width, so we can set up the following equation:
Length * Width = Area
(4w) * w = 64
Simplifying, we have:
4w^2 = 64
Dividing both sides by 4:
w^2 = 16
Taking the square root of both sides:
w = ±4
Since the width cannot be negative in this case, we discard the negative value. Therefore, the width of the play ground is 4 yards.
To find the length, we can substitute the value of the width back into the expression for the length:
Length = 4w = 4 * 4 = 16 yards
So the correct answer is a.) L = 16 yards; w = 4 yards.