Math

Is the LCD of x/2x-4 and 5x/12x-24 not 24(x-2)? The original question is x/2x-4 + 5x/12x-24 and I factored the denominators first so that I could find the LCD. And I got:

x/2(x-2) + 5x/12(x-2)

After that, I multiplied up to the LCD and got:

x/2(x-2) + 5x/12(x-2)
= x/2(x-2)*(12/12) + 5x/12(x-2)*(2/2)
= 12x/24(x-2) + 10x/24(x-2)
= 22x/24(x-2)

What did I do wrong?

  1. 👍 0
  2. 👎 0
  3. 👁 151
  1. 2x-4 = 2(x-2)
    12x-24 = 12(x-2)

    So, the LCD is 12(x-2), not 24(x-2)

    (6x+5x) / 12(x-2)
    11x/12(x-2)

    This is the same as your answer, if you cancel a factor of 2 which you did not need in the LCD.

    1. 👍 0
    2. 👎 0
    posted by Steve
  2. I don't think I exactly understand how to figure out the LCD. So how do you know that the LCD is 12(x-2) not 24(x-2)?

    1. 👍 0
    2. 👎 0
    posted by Emily J

Respond to this Question

First Name

Your Response

Similar Questions

  1. algebra1

    could you walk-through the steps to solving this problem because I am stuck; 3x-5(3x-7)=2(x+9)+45 Let me know if you have a question in any step. 3x-5(3x-7)=2(x+9)+45 3x-15x+35= 2x+18+45 -12x+35 = 2x+63 -35 -35 -12x= 2x +63-35

    asked by unknown on March 21, 2007
  2. Algebra. Please check my answers

    Evaluate a/b+c^d for a=6,b=3,c=4 and d=5 A.42*** B.18 C.82 D.360 What is the simplified form of the expression ? -(12x-8y) A.12x+8y B.12x-8y***** C.-12x+8y D.-12x-8y

    asked by Help please on September 3, 2015
  3. algebra2

    1/3 - 5/6 = 1/X SOLVE 1/3 - 5/6 = 1/X Let's remove the denominators by multiplying by 12X 12X*(1/3) - 12X*(5/6) = 12X*(1/X) Clear the fractions. 4X - 10X = 12 -6X=12 multipy by -1 6X=-12 Divide both sides by 6 6X/6 = -12/6 X = -2

    asked by maria on January 16, 2007
  4. math

    how do i do x2+12x+32 x2+12x = 14x+32 subtract 14x from each side 14x=32 divide by 2 7x=16 x=16/7, which is 2 and 2/7 ok maybe you typed that question wrong? is it x^2 + 12x + 32 ? if it is then the solution is: (x+8)(x+4) because

    asked by bob on February 14, 2007
  5. Polynomial Fucntion Problem

    Could you help me with the following problem, I don't understand how to do it. Am I suppose to use the linear factorization theorem? Find an nth degree polynomial function with real coefficients satisfying the given conditions. 1.

    asked by Jen on October 9, 2007
  6. Calculus!! HELP!!

    1) The sides of the triangle shown increase in such a way that (dz/dt=1) and (dx/dt=(3dy/dx)) At the instant when x = 12 and y = 5, what is the value of dx/dt? 2) Let f(x) = x^3 − 4. Which of these is the equation for the normal

    asked by Prince@18 on December 17, 2016
  7. calc

    What is dy/dx of y=12/12X-y^3 ???? Any idea anyone??? y=12/12X-y^3 I assume you mean... y=12/(12X-y^3) 12Xy-y^4=12 12x dy/dx + 12y -4y^3 dy/dx=0 dy/dx (12x -4y^3)=-12y solve for dy/dx

    asked by nick on December 7, 2006
  8. math

    The rectangle given has a perimeter of 14 units. Find the value(s) of x by factoring a quadriatic equation. one side= 12/(x+1) other side= 6/(4-x) Remember that the perimeter of a rectangle is: P = 2L + 2W Note: P = perimeter, L =

    asked by Shay on January 17, 2007
  9. Algebra

    Can someone help me with this please. Andrew factored the expression 20x^3-12x^2+8x as 4x(5x^2-12x^2+8x) but when melissa applied the distributive law and multiplied out 4x(5x^2-12x^2+8x)she got 20x^3-48x^3+32x thus Andrews

    asked by Anonymous* on August 2, 2012
  10. Derivatives

    What is the fourth derivative of f(x)= e^-x^2. I got f''(x)=-2e^-x^2 + 4x^2e^-x^2 i need some help on find f''''(x) You have f(x) = e-x2 then f'(x) = -2x*e-x2 = -2x*f(x) f"(x) = (4x2 - 2))e-x2 = f(x)*(4x2 - 2)) f"'(x)= f'(x)*(4x2

    asked by 413 on October 24, 2006

More Similar Questions