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algebra1
could you walkthrough the steps to solving this problem because I am stuck; 3x5(3x7)=2(x+9)+45 Let me know if you have a question in any step. 3x5(3x7)=2(x+9)+45 3x15x+35= 2x+18+45 12x+35 = 2x+63 35 35 12x= 2x +6335
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1/3  5/6 = 1/X SOLVE 1/3  5/6 = 1/X Let's remove the denominators by multiplying by 12X 12X*(1/3)  12X*(5/6) = 12X*(1/X) Clear the fractions. 4X  10X = 12 6X=12 multipy by 1 6X=12 Divide both sides by 6 6X/6 = 12/6 X = 2
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What is dy/dx of y=12/12Xy^3 ???? Any idea anyone??? y=12/12Xy^3 I assume you mean... y=12/(12Xy^3) 12Xyy^4=12 12x dy/dx + 12y 4y^3 dy/dx=0 dy/dx (12x 4y^3)=12y solve for dy/dx
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Can someone help me with this please. Andrew factored the expression 20x^312x^2+8x as 4x(5x^212x^2+8x) but when melissa applied the distributive law and multiplied out 4x(5x^212x^2+8x)she got 20x^348x^3+32x thus Andrews
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