Calculus Help Stuck Part 2?
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calc
need to find: lim as x > 0 of 4(e^2x  1) / (e^x 1) Try splitting the limit for the numerator and denominator lim lim x>0 4(e^2x1) (4)x>0 (e^2x1) ______________ = ________________ lim lim x>0 e^X1 x>0 e^x1 Next solve for
asked by brian on September 26, 2006 
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Find the following limits algebraically or explain why they don’t exist. lim x>0 sin5x/2x lim x>0 1cosx/x lim x>7 x7/x7 lim x>7 (/x+2)3/x7 lim h>0 (2+h)^38/h lim t>0 1/t  1/t^2+t
asked by angie on March 15, 2012 
Calculus  ratio test
infinity of the summation n=1: (e^n)/(n!) [using the ratio test] my work so far: = lim (n>infinity)  [(e^n+1)/((n+1)!)] / [(e^n)/(n!)]  = lim (n>infinity)  [(e^n+1)/((n+1)!)] * [(n!)/(e^n)]  = lim (n>infinity) 
asked by COFFEE on July 29, 2007 
calculus  ratio test
infinity of the summation n=1: (e^n)/(n!) [using the ratio test] my work so far: = lim (n>infinity)  [(e^n+1)/((n+1)!)] / [(e^n)/(n!)]  = lim (n>infinity)  [(e^n+1)/((n+1)!)] * [(n!)/(e^n)]  = lim (n>infinity) 
asked by COFFEE on July 30, 2007 
Math
Find the limit of the sequence 2ln(1+3n)  ln(4+n^2) What I did: lim as n approach inf of an = 2*lim ln (1+3n)/(4+n^2) = 2 * lim ln (1/n^2 + 3n/n^2) / (4/n^2 + n^2/n^2) = 2 * lim ln (1/n^2 + 3/n) / (4/n^2 + 1) = 2 * lim ln
asked by Helloo on April 25, 2019 
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Determine the limit of the trigonometric function (if it exists). 1. lim sin x / 5x (x > 0) 2. lim tan^2x / x (x >0) 3. lim cos x tan x / x (x > 0)
asked by ac on October 1, 2007 
Calc Please Help
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 14, 2010 
calc
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 13, 2010 
Calc. Limits
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 13, 2010 
calculus  ratio test
Posted by COFFEE on Sunday, July 29, 2007 at 6:32pm. infinity of the summation n=1: (e^n)/(n!) [using the ratio test] my work so far: = lim (n>infinity)  [(e^n+1)/((n+1)!)] / [(e^n)/(n!)]  = lim (n>infinity) 
asked by COFFEE on July 29, 2007 
Calculus
Find the indicated limits. If the limit does not exist, so state, or use the symbol + ∞ or  ∞. f(x) = { 2  x if x ≤ 3 { 1 + 3x  x^2 if x > 3 a) lim 3+ f(x) x>3 b) lim 3 f(x) x>3 c) lim f(x) x>3 d) lim ∞ f(x) x>3
asked by Blue on October 8, 2011