Math

1) A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given.

a) find BC, the distance from Tower 2 to the plane, to the nearest foot.
b) find CD, the height of the plane from the ground, to the nearest foot.

if you google this question, you will find the image that goes along with it. All the other sites have bad explanations and I'm very confused. Any help would be appreciated. Thank you!

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  1. If CD=h and BC=x, then

    h/x = tan24°
    h/(x+7600) = tan16°

    or,

    h = 0.4452x
    h = 0.2867x + 2179.2649

    0.4452x = 0.2867x + 2179.2649
    BC = x = 13750
    CD = h = 6121

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  2. Thank you so much! this was so much help!

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  3. but tans and stuff only work on right triangles

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  4. I still don't understand

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  5. stoppppp thattt hurtssss

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  6. Freak....

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  7. Rukia, I think that if this is a place where young people get together, then you should make all feel welcome, so refrain from any rude or harsh comments. :)

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  8. one of you, shut yo ah up

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  9. I agree with Steve, but for finding the tan 24º that's wrong. To find the tan, it's the opposite leg divided by the adjacent leg (not the hypotenuse). So it would be h/BD=tan24º.

    You could use h/x, but then it would be sin:
    h/x=sin24º
    since sin is the opposite leg divided by the hypotenus.

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