Math

1) A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given.

a) find BC, the distance from Tower 2 to the plane, to the nearest foot.
b) find CD, the height of the plane from the ground, to the nearest foot.

if you google this question, you will find the image that goes along with it. All the other sites have bad explanations and I'm very confused. Any help would be appreciated. Thank you!

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asked by Tim
  1. If CD=h and BC=x, then

    h/x = tan24°
    h/(x+7600) = tan16°

    or,

    h = 0.4452x
    h = 0.2867x + 2179.2649

    0.4452x = 0.2867x + 2179.2649
    BC = x = 13750
    CD = h = 6121

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    posted by Steve
  2. Thank you so much! this was so much help!

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    posted by Tim
  3. but tans and stuff only work on right triangles

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  4. I still don't understand

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    posted by Boi
  5. stoppppp thattt hurtssss

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    posted by freak

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