Create an image of a blank piece of graph paper with a two-dimensional coordinate system. Mark point A at coordinates (3, 2). Depict a dotted line extending from point A in the direction of (1, -1). The length of this line should represent 4 units. Label this line as AB and show it with an arrowhead, pointing in the direction of (1, -1). Leave ample space around this setup for potential notes.

A is (3, 2) and point B is 4 units from A in the direction (1,-1)

Find AB(arrow).
Find the coordinates of B.

I can't do this question, Ive attempted it many times.

This answer isn't all too clear

AB = 4 divided by |(1, -1)| times (1, -1)
AB = 4/√2 times (1, -1)
AB = (4/√2, -4/√2) = (2√2, -2√2)

Next is Finding OB
OB = OA + AB
OB = (3,2) + (2√2, -2√2)
OB = (3 + 2√2, 2 - 2√2)

Now we can deduce the point B to be at
(3 + 2√2, 2 - 2√2)

Oh no, it seems like you're really "A-d" at this question! Don't worry, I've got your back, even if it makes me look a bit "cl-Sine-tered". Let's tackle it together!

To find AB (arrow), we need to calculate the distance between points A (3, 2) and B. We can use the distance formula:

AB = √[(x₂ - x₁)² + (y₂ - y₁)²]

In this case, x₁ = 3, y₁ = 2 (coordinates of A) and x₂ and y₂ are the unknown coordinates of B. We know that B is 4 units away from A in the direction (1, -1).

To find the coordinates of B, we can add or subtract the direction vector (1, -1) from point A. Let's use some "add-itude" (attitude)!

x₂ = x₁ + direction vector x-coordinate = 3 + 1 = 4
y₂ = y₁ + direction vector y-coordinate = 2 + (-1) = 1

Therefore, the coordinates of point B are (4, 1).

Now, let's calculate the distance AB (arrow):

AB = √[(4 - 3)² + (1 - 2)²]
= √[1² + (-1)²]
= √(1 + 1)
= √2

So, AB (arrow) is approximately √2 units. I hope this helps you "sqrt" out your problem!

To solve this question, we need to use the concept of vector addition and the formula for finding a point that is a certain distance away from another point in a specific direction.

Let's break down the steps to solve this problem:

Step 1: Understanding the given information
From the question, we know that point A is located at (3, 2), and we are given that point B is 4 units away from point A in the direction of (1, -1).

Step 2: Finding vector AB (arrow)
To find vector AB, we need to subtract the coordinates of point A from the coordinates of point B. Given that point A is (3, 2) and point B is 4 units away from A in the direction (1,-1), we can calculate AB as follows:
AB = B - A
= (3 + 4(1), 2 + 4(-1))
= (7, -2)

Therefore, the vector AB (arrow) is (7, -2).

Step 3: Finding the coordinates of point B
To find the coordinates of point B, we need to add the values of vector AB to the coordinates of point A.
B = A + AB
= (3, 2) + (7, -2)
= (3 + 7, 2 + (-2))
= (10, 0)

Therefore, the coordinates of point B are (10, 0).

In conclusion, AB (arrow) is (7, -2), and the coordinates of point B are (10, 0).

Since |B| = 4, B = <4/√2,-4/√2> = <2√2,-2√2>

AB = B-A = (2√2-3,-2√2-2)

I don't understand how you know that the modulus of B is 4