A 3.10 kg block is pushed along a floor by a constant applied force that is horizontal and has a magnitude of 43.5 N. What is the coefficient of kinetic friction between the block and the floor?

I tried dividing the N by the KG and vise versa but it didn't work

I guess it is at constant velocity

m g = 3.1*9.81 = 30.4 N weight

mu m g = 43.5 N
mu = 43.5/30.4 = 1.43

To find the coefficient of kinetic friction between the block and the floor, you need to use the formula that relates the magnitude of the applied force, the coefficient of kinetic friction, and the normal force.

The normal force is the force exerted by a surface perpendicular to the object in contact with it. In this case, since the block is on the floor, the normal force exerted by the floor on the block is equal to the weight of the block. The weight of an object can be calculated using the formula:

Weight = mass x gravitational acceleration

The gravitational acceleration on Earth is approximately 9.8 m/s^2.

In this case, the weight of the block is:

Weight = 3.10 kg x 9.8 m/s^2

Once you have calculated the weight of the block, you can use it to find the magnitude of the frictional force:

Frictional force = coefficient of kinetic friction x normal force

The magnitude of the frictional force can also be calculated using the formula:

Frictional force = applied force - net force

Since the block is being pushed with a constant applied force, the net force can be calculated using Newton's second law:

Net force = mass x acceleration

In this case, the acceleration is determined by dividing the applied force by the mass of the block:

Acceleration = applied force / mass

Once you have calculated the net force, you can equate it to the magnitude of the frictional force and solve for the coefficient of kinetic friction.

Using these steps, you should be able to find the coefficient of kinetic friction between the block and the floor.