Einswine has a mass of 300 kg. He sits on an ideal spring. Before he sits on the spring it is 2 m tall. After he sits on the spring it is only 1.5 m tall. What is the spring constant of the spring?

spring consant=mg/.5m=300*9.8/.5

= 600*9.8 N/m

To find the spring constant, we can make use of Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. Mathematically, this can be expressed as:

F = k * x

where F is the force applied to the spring, k is the spring constant, and x is the displacement from the equilibrium position.

In this case, we can calculate the force applied by the weight of Einswine using the relationship between force, mass, and acceleration due to gravity:

F = m * g

where m is the mass of Einswine and g is the acceleration due to gravity (9.8 m/s²).

Therefore, we can calculate the force applied by Einswine's weight:

F = 300 kg * 9.8 m/s²

Now we need to find the displacement of the spring, which is the difference in height before and after Einswine sits on it:

x = 2 m - 1.5 m

Now, let's substitute the values into Hooke's Law equation and solve for the spring constant (k):

300 kg * 9.8 m/s² = k * (2 m - 1.5 m)

2940 N = 0.5 k

k = 2940 N / 0.5

k = 5880 N/m

Therefore, the spring constant of the spring is 5880 N/m.