the volume of the shape below is placed into a bow that is 10 feet tall and the area of the base is 48ft squared feet. to the nearest tenth what is the remaining space.
The figure is a sphere that has a radius of 6 ft. r=6ft
I really need help figuring how to do this
box not bow, srry
volume of box = base area x height
= 48(10) ftt^3
= 480 ft^3
volume of sphere = (4/3)(pi)(6^2)
= 48pi ft^3
subtract the two volumes
thx
To find the remaining space in the bowl after placing the volume of the sphere inside, follow these steps:
Step 1: Calculate the volume of the sphere:
The volume of a sphere can be calculated using the formula:
V = (4/3) * π * r^3
where V is the volume and r is the radius.
Plug in the value of the radius given in the question:
r = 6 ft
Using the formula, calculate the volume:
V = (4/3) * π * (6 ft)^3
V ≈ 904.78 cubic feet (rounded to the nearest hundredth).
Step 2: Calculate the volume of the bowl:
The volume of the bowl can be calculated using the formula:
V = A * h
where V is the volume, A is the area of the base, and h is the height.
Plug in the values of the area of the base and height given in the question:
A = 48 sq ft
h = 10 ft
Using the formula, calculate the volume:
V = 48 sq ft * 10 ft
V = 480 cubic feet.
Step 3: Calculate the remaining space:
To find the remaining space, subtract the volume of the sphere from the volume of the bowl.
Remaining Space = Volume of the Bowl - Volume of the Sphere
Remaining Space = 480 cubic feet - 904.78 cubic feet
Remaining Space ≈ -424.78 cubic feet (rounded to the nearest hundredth).
The remaining space is approximately -424.78 cubic feet.