Physics

A 25 kg box is along a horizontal floor and a force of 400 N pushes the box with an angle of 50 degree with the horizontal. Starting from rest, the box achieves a velocity of 2 m/s in a time of 4 seconds. Find the coefficient of sliding friction between the box and the floor. Help please. I need a solution

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  1. FFirst find a. Then
    400 cos50 - ยต(mg+400 sin50) = ma
    Solve for mu

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    posted by Chanz

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