There's a frog at the bottom of a 30-foot well. The frog will rise 3 feet in the morning & would slid down 2 feet in the evening. If the frog will start on February 1, what date will it reach the top?
If it goes up 3 feet then slides down 2 feet, then it goes up 1 foot a day, so it would take 30 days to get up to the top
morning of day 1 -- 3 ft
evening of day 1 -- 1 ft ,(3-2)
morning of day 2 -- 4 ft
evening of day 2 -- 2
...
morning of day 27 -- 29 ft
evening of day 27 -- 27 ft
morning of day 28 -- 30 ft
He has reached the top, no sliding back
He will reach the top on Feb 28th
To determine the date on which the frog will reach the top of the well, we need to consider the frog's daily progress and the total distance it needs to cover.
Given that the frog rises 3 feet in the morning but slides down 2 feet in the evening, its net progress per day is 3 feet - 2 feet = 1 foot.
The frog needs to cover a total distance of 30 feet to reach the top of the well. At a pace of 1 foot per day, it will take 30 days for the frog to reach the top.
Starting on February 1, we can count 30 days forward to determine the date.
Therefore, the frog will reach the top of the well on March 2.