Mathematics
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posted by Reiny
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I would let #1 = x. Then #2 = x+1 #3 = x+2 #4 = x+3 The problem says we want the sum of the first three. That will be x + (x + 1) + (x + 2) and that should be 60 more than the fourth. The fourth is x + 3; therefore, set them equal
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