chemistry

A sample of neon effuses from a container in 73 seconds. The same amount of an unknown noble gas requires 149 seconds.
Identify the gas.

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3. 👁 685
1. Use Graham's law of effusion.

rateX/rateNe= sqrt (molmassNe/molmassx)

solve for mole mass of x.

Now notice this: rate above is volume/time

You are given time. So if you want to plug in the given times, the equation becomes

time1/timeNe=sqrt(molmass1/timeNe)

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2. i am not doing it right , first i got Hydrogen and then Helium...im not sure what im doing wrong

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posted by nikki
3. 149/73= sqrt(molmassX/20.18)
molmassX=4.16*20.18

The closest Nobel element is Radon.

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4. The closest would be Krypton, not Radon

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posted by Ben
5. wouldnt the equation be 149/73=sqrt(20.18/molar massx)

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posted by cat
6. No it is inverse

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posted by Kris
7. How did you get the 4.16?

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posted by Morgan
8. 149 Ne/73 unknown = sqrt(MM unknown/20.183)
Square root the denominator

2.0411 = sqrt(MM unknown)/ 4.4925
multiply the denominator to isolate the unknown

2.0411 x 4.4925 = sqrt(MM unknown)

9.16972 = sqrt(MM)
Square both sides,

84.083 = unknown molar mass, closest element is the noble gas Radon.

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posted by Matt
9. Bleh, I meant Krypton, not Radon.

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posted by Matt

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