chemistry

A sample of neon effuses from a container in 73 seconds. The same amount of an unknown noble gas requires 149 seconds.
Identify the gas.

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asked by nikki
  1. Use Graham's law of effusion.

    rateX/rateNe= sqrt (molmassNe/molmassx)

    solve for mole mass of x.

    Now notice this: rate above is volume/time

    You are given time. So if you want to plug in the given times, the equation becomes

    time1/timeNe=sqrt(molmass1/timeNe)

  2. i am not doing it right , first i got Hydrogen and then Helium...im not sure what im doing wrong

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    posted by nikki
  3. 149/73= sqrt(molmassX/20.18)
    molmassX=4.16*20.18

    The closest Nobel element is Radon.

  4. The closest would be Krypton, not Radon

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    posted by Ben
  5. wouldnt the equation be 149/73=sqrt(20.18/molar massx)

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    posted by cat
  6. No it is inverse

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    posted by Kris
  7. How did you get the 4.16?

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    posted by Morgan
  8. 149 Ne/73 unknown = sqrt(MM unknown/20.183)
    Square root the denominator

    2.0411 = sqrt(MM unknown)/ 4.4925
    multiply the denominator to isolate the unknown

    2.0411 x 4.4925 = sqrt(MM unknown)

    9.16972 = sqrt(MM)
    Square both sides,

    84.083 = unknown molar mass, closest element is the noble gas Radon.

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    posted by Matt
  9. Bleh, I meant Krypton, not Radon.

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    posted by Matt

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