Factor completely.
32a^2+96a+72
I tried to work it our but I can't seem to get the correct answer.
Thanks!
Did you first look for the HCF ?
I see:
8(4a^2 + 12a^2 + 9)
hint#2: Did you notice the perfect squares at front and end of the trinomial?
Yes, I did.
Thanks
To factor the quadratic expression 32a^2 + 96a + 72 completely, you can use the factoring by grouping method. Here's how you can do it:
Step 1: Look for the common factor in all three terms, which is 8.
8(4a^2 + 12a + 9)
Step 2: Now you need to factor the trinomial inside the parentheses, which is 4a^2 + 12a + 9.
The factors of 4a^2 are 2a and 2a.
The factors of 9 are 3 and 3.
8(2a + 3)(2a + 3)
Step 3: Combine the common factors.
8(2a + 3)^2
Thus, the completely factored form of 32a^2 + 96a + 72 is 8(2a + 3)^2.