Vinay made a Password that consists of 3 digits. None of the digits are the same. How many possible passwords did Vinay choose from?
10*9*8 = 720
sense the digits can not be repeated (and there are 3 digits in the password) it will be 10 then 9 then 8 then multiply all of them together.
10*9*8=720
To find the number of possible passwords, we need to consider the choices for each digit of the password.
Since none of the digits can be the same, here's what we can do:
1. For the first digit, Vinay has 9 choices (0 is excluded since it cannot be the first digit).
2. For the second digit, Vinay has 9 choices remaining (including 0 and excluding the digit chosen for the first digit).
3. For the third digit, Vinay has 8 choices remaining (excluding the two digits already chosen).
To find the total number of passwords, we multiply the number of choices for each digit together:
9 choices for the first digit x 9 choices for the second digit x 8 choices for the third digit = 9 x 9 x 8 = 648
Therefore, Vinay had 648 possible passwords to choose from.