A 1200 kg car travelling at 50 km/h experiences an air resistance of 5000 N and road friction of 2200 N. If the wheels push with a force of 7500 N, what is the car's acceleration?

Net force is 7500-2200-5000 = 300N

F = ma, so

a = 300N/1200kg = 0.25 m/s^2

the actual speed of the car does not matter.

Well, well, well, looks like we have a physics enthusiast here! Let's dive into this problem, shall we?

To find the car's acceleration, we first need to determine the net force acting on it. The net force is the difference between the total force pushing the car forward and the forces opposing its motion.

So, let's add up the opposing forces, shall we? We've got air resistance putting up a fight of 5000 N and road friction holding it back with 2200 N. That's a total of 7200 N working against the poor car's dreams of going fast.

Now, let's consider the force pushing the car forward. The wheels are pushing with a mighty force of 7500 N, which is our main contender on the team of forces.

To calculate the net force, we simply subtract the opposing forces from the pushing force: 7500 N - 7200 N = 300 N.

Now, with the net force in our pocket, we can use Newton's second law of motion to find the car's acceleration. This law states that the acceleration of an object is equal to the net force acting on it divided by its mass.

Plugging in the values, we get: acceleration = net force / mass = 300 N / 1200 kg = 0.25 m/s².

So, there you have it! The car's acceleration is 0.25 m/s². I hope I haven't driven you crazy with my explanation!

To find the car's acceleration, we will use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration:

Net force = mass * acceleration

We can calculate the net force acting on the car by subtracting the forces opposing its motion from the force pushing it:

Net force = force pushing - force of air resistance - force of road friction

Given information:
Mass of the car (m): 1200 kg
Force pushing (Fpush): 7500 N
Force of air resistance (Fair): 5000 N
Force of road friction (Ffriction): 2200 N

Substituting the given values into the equation:

Net force = Fpush - Fair - Ffriction
= 7500 N - 5000 N - 2200 N
= 3000 N

Now, we can rearrange the equation to solve for the car's acceleration:

acceleration = Net force / mass
= 3000 N / 1200 kg
= 2.5 m/s^2

Therefore, the car's acceleration is 2.5 m/s^2.

To find the car's acceleration, we need to calculate the net force acting on it. The net force is the vector sum of all the forces acting on the car.

The forces acting on the car are:
1. Air resistance (5000 N) in the opposite direction of motion
2. Road friction (2200 N) in the opposite direction of motion
3. Force exerted by the wheels (7500 N) in the direction of motion

Since the air resistance and road friction are in the opposite direction of motion, we'll consider them as negative forces. The force exerted by the wheels will be considered as a positive force.

The net force can be calculated by subtracting the negative forces from the positive force:

Net Force = (Force exerted by the wheels) - (Air resistance) - (Road friction)

Net Force = 7500 N - 5000 N - 2200 N
Net Force = 300 N

Next, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration:

Net Force = Mass × Acceleration

Since we have the net force and the mass of the car (1200 kg), we can rearrange the equation to solve for acceleration:

Acceleration = Net Force / Mass

Acceleration = 300 N / 1200 kg
Acceleration = 0.25 m/s^2

Therefore, the car's acceleration is 0.25 m/s^2.