solve for x if 1/15(6+x)=1/6(x+3)
what u did was wat i meant (Reiny) thanks both of u
To solve for x in the equation (1/15)(6+x) = (1/6)(x+3), we can follow these steps:
Step 1: Remove the fractions by multiplying each term on both sides of the equation by the least common denominator (LCD), which is 30.
(30)*(1/15)(6+x) = (30)*(1/6)(x+3)
Simplifying the equation gives us:
2(6+x) = 5(x+3)
Step 2: Distribute the coefficients on both sides of the equation.
12 + 2x = 5x + 15
Step 3: Combine like terms by moving the variables to one side of the equation and the constants to the other side.
2x - 5x = 15 - 12
Simplifying the equation gives us:
-3x = 3
Step 4: Solve for x by dividing both sides of the equation by -3.
x = 3 / -3
Simplifying gives us:
x = -1
Therefore, the value of x that satisfies the equation (1/15)(6+x) = (1/6)(x+3) is -1.
are the ( ) quantities in the numerator or denominators?
both
both? then you need to write it such as it is. Right now, both are in the denominator.
i do not know how to,but take for instance it was for the numerator alone
the way you typed according to BEDMAS
(1/15)(6+x)=(1/6)(x+3)
multiply both sides by 30
2(6+x) = 5(x+3)
now it is easy, carry on
What Bob meant was:
did you mean,
1/(15(6+x)) =1/(6(x+3)) ?
then we have an entirely different ballgame