Calculus

A festivals being planned. The planners need to enclose to adjacent 200 M^2 areas with fencing. They have budgeted \$1000 for fencing. Fencing currently cost \$10/meter. The diagram of the area is as follows:

(The diagram is 2 adjacent squares, the areas of both squares are 200 and the total area is 400)

1. Write an equation representing the total length of fence, L, needed in terms of the dimensions, X and Y, of the fence.

2.right in equation representing the total area of the venue in terms of the dimensions.

3. Showing your work, state what is a planners can afford the fencing on their budget.

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1. If each square has side x, then x = √200, and the total fence is 7√200 m

I feel that the two areas are in fact not squares, but rectangles.

In that case, if each rectangle has dimensions x by y, and they are separated by a side of length x, then the total fence is 3x+4y and the total area is 2xy.

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posted by Steve

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