Trig

Find the length of a chord intercepted by a central angle of 25 degrees in a circle of radius 30 feet

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  1. let the length of the chord be 2x ft
    Drop a perpendicular from the central vertex to the chord
    then sin 12.5 = x/30
    x = 30sin12.5
    2x = 60sin12.5 = 12.9864

    or by cosine law:
    let the length of the chord be c
    c^2 = 30^2 + 30^2 - 2(30)(30)cos25
    = 168.64598..
    c = 12.9864 , same as above

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