Each of my digits is add. They add up to 12. I have 4 digits. What am I?

add = odd ??

notice that
12 = 7+5+1+1
or
12= 3+5+3+1
12 = 7+3+1+1
12 = 9+1+1+1

see if you can find any others.

now each of my choices can be arranged in different orders

7,5,1,1 ---> yields 4!/2! or 12 of them
3,5,3,1, yields 4!/2! = 12 of them
7,1,1,1,1
etc

one of them is 5711 another is 3171

scrap the 7,5,1,1 combination, they don't add up to 12

also scrap the 7,1,1,1,1, there should only be 4 digits.

To determine the number that fits your description, we can start by analyzing what we know. You have four digits, and the sum of these digits is 12.

Let's list out the possible combinations of four digits that add up to 12:

1 + 1 + 1 + 9 = 12
1 + 1 + 2 + 8 = 12
1 + 1 + 3 + 7 = 12
1 + 1 + 4 + 6 = 12
1 + 2 + 2 + 7 = 12
1 + 2 + 3 + 6 = 12
1 + 2 + 4 + 5 = 12
1 + 3 + 3 + 5 = 12
2 + 2 + 2 + 6 = 12
2 + 2 + 3 + 5 = 12
2 + 3 + 3 + 4 = 12

After examining all the possible combinations, we can see that the number that matches your description is 1 + 2 + 3 + 6 = 12.

Therefore, the number you are is 1236.