Geometry
Find the area of a hexagon with the indicated apothem:
6 sqr root 3
108 sqr root 3 in.^2
432 sqr root 3 in.^2
96 sqr root 3 in.^2
216 sqr root 3 in.^2
Last question, don't know. Please help? Thanks

Area = 1/2 x perimeter x apothem
= 1/2 (6s)(6√3)
once you tell me what the side (s) of the hexagon is, we an finish the question
posted by Reiny

They don't tell you the sides, the apothem is all they give you.
posted by SkatingDJ

So, I guess we can't find the area, since we need the side
posted by Reiny

Hm, I mean, there has to be a way to figure the side out with just the apothem. Problem is that I'm not good with formulas or square roots.
First off, what is the apothem? What is 6 square root 3?posted by SkatingDJ

ok, ok
I stand corrected, there is a way, we have an angle.
The apothem is the distance from the centre to the midpoint of a side
Let's look at one of the triangles of the hexagon.
It has a central angle of 60
so in a rightangled triangle formed by the apothem and half the base, I'll call it x
x/6√3 = tan 30
x = 6√3tan30
base = 12√3tan30= 12
area = Area = 1/2 x perimeter x apothem
= (1/2)(72)(6√3)
= 216√3 units^2posted by Reiny

Unit 5: Area
Lesson 4: Perimeters and Areas of Similar Figures
Perimeters and Areas of Similar Figures Quiz
1) A  14.04cm^2
2) A  34cm^2
3) A  144.5cm^2
4) D  12cm
5) A  144 + 72squareroot3
6) B  15.9ft^2
7) D  72squareroot3
8) B  73.5squareroot3cm^2
9) C  5 : 4 and 25 : 16
10) C  3181m^2
11) A  $81.25
12) D  the area would not change
13) D  216squareroot3in^2
100%posted by Raaayleeee
Respond to this Question
Similar Questions

Algebra2/Trig
sqr(x^24)+(x^2)/x^2+1 I got ((x^2+1)*sqr(x^24)+x^2)/x^2+1 But my teacher gave (sqr(x^24)+x^2)/x^2+1 I did the problem over again but I can't figure out why my teacher got the answer. Can someone confirm that my teacher is right 
Calc
How close is the semi circle y= sqr.root of 16x^2 to the point (1, sqr.root 3)? using Optimization 
Math
Find the quotient function f/g for f(x)=sqr(x+1) and g(x)= sqr( x1). My Answer: sqr(x+1)/sqr( x1) sqr(x^21)/ (x1) However, I also have to state the restrictions to the domain and range, which I do not know how to do. Could 
Math
Find the quotient function f/g for f(x)=sqr(x+1) and g(x)= sqr( x1). My Answer: sqr(x+1)/sqr( x1) sqr(x^21)/ (x1) However, I also have to state the restrictions to the domain and range, which I do not know how to do. Could 
Algebra 2
Ok, so I'm trying to find the inverse of each function. We're learning about Inverse Functions and Relations. The problem is f(x)=sqr.root of x/6 The sqr root is confusing me. 
algebra
sqr root of 3a + 9(sqr root of 27a^3) 
algebra
(sqr root of 2 + 3*sqr root of 5)(sqr root of 23*sqr root of 5) 
math
I have a question I have been working on since yesterday and I am not making this up. I couldn't get the right answer. If sin theta = 2/3, which of the following are possible? A: cos theta= the sqr rt of 5/3 and tan theta =2/3. 
calculus
Is this the correct answers for these questions Verify the means value theorem holds on the interval shown. Then, find the value c such that f'(c)=(f(b)f(a))/(ba) b.f(x)=x^3=x4 on [2,3] c= square root 7/3 c. f(x)= x^3 on 
Physical chemistry
help! I am trying to figure out how to convert from equation one to equation two. I have spent two hours on this and cannot figure it out. I would greatly appreciate if someone could help me out on this. Equation1: v= sqr root