A 3.50-kg bucket is attached to a cylindrical, massive pulley with a radius of 0.440 m. The bucket starts from rest and falls for 1.3 s into a well. The tension in the rope is 13.03N.
What is the magnitude of the linear acceleration of the falling bucket?
Pretty sure you need the mass of the pulley.
To find the magnitude of the linear acceleration of the falling bucket, we can use Newton's second law of motion:
F_net = m * a
Where:
F_net is the net force acting on the bucket
m is the mass of the bucket
a is the linear acceleration of the bucket
In this case, the net force is equal to the tension in the rope, so we can rewrite the equation as:
Tension = m * a
Rearranging the equation, we get:
a = Tension / m
Given that the tension in the rope is 13.03 N and the mass of the bucket is 3.50 kg, we can substitute these values into the equation to find the magnitude of the linear acceleration of the falling bucket:
a = 13.03 N / 3.50 kg = 3.72 m/s²
Therefore, the magnitude of the linear acceleration of the falling bucket is 3.72 m/s².