John carries a 200 N suitcase up three flights of stairs (a height of 10 m) and then pushes it with a horizontal force of 50 N at a constant speed of 0.5 m/s for a horizontal distance of 35 meters. How much work does Ben do on his suitcase during this entire motion?

Ben doesn't do any work because John is the one carrying it lolol

work up the stairs=200*10=2000J

work horizontal=50*35=you do it.
total work= sum of those two

I really appreciate for helping me

To calculate the work done on the suitcase, we need to calculate the work done in each part of the motion separately and then add them up.

1. Work done while lifting the suitcase:
The work done when lifting the suitcase against gravity is given by the formula:
Work = Force * Distance * Cosine(angle)

In this case, the force is the weight of the suitcase, which is 200 N, the distance is the vertical height of the stairs, which is 10 m, and the angle between the force and distance vectors is 0 degrees since they are in the same direction. So the formula becomes:
Work = 200 N * 10 m * Cos(0°)

Since Cos(0°) = 1, the work done while lifting the suitcase is:
Work = 200 N * 10 m * 1 = 2000 J (Joules)

2. Work done while pushing the suitcase horizontally:
The work done when pushing the suitcase horizontally is given by the formula:
Work = Force * Distance * Cosine(angle)

In this case, the force is 50 N, the distance is 35 m, and the angle between the force and distance vectors is 180 degrees since they are in opposite directions. So the formula becomes:
Work = 50 N * 35 m * Cos(180°)

Since Cos(180°) = -1, the work done while pushing the suitcase is:
Work = 50 N * 35 m * (-1) = -1750 J (Joules)

Adding up the work done in both parts of the motion, we get:
Total Work = 2000 J + (-1750 J) = 250 J (Joules)

Therefore, the total work done by John on his suitcase during the entire motion is 250 Joules.