For the H 3 CNCO molecule, (Note: The atoms are bonded in the order CNCO, with the three H atoms bonded to the first carbon atom.) answer the following questions.
What is the ideal H-C-H bond angle?
(0, 30, 45, 60, 90, 109, 120, 145, or 180.)
What is the ideal N-C-O bond angle?
(0, 30, 45, 60, 90, 109, 120, 145, or 180.)
What is the ideal C-N-C bond angle?
(0, 30, 45, 60, 90, 109, 120, 145, or 180.)
Chem
To determine the ideal bond angles in the H3CNCO molecule, we can first draw the Lewis structure.
The Lewis structure for H3CNCO shows that the molecule has a linear structure.
To determine the bond angles, we need to consider the arrangement of the atoms around the central carbon atom (C).
In this case, the three hydrogen atoms (H) are bonded to the central carbon atom (C).
For a linear molecule like this, the H-C-H bond angle is 180 degrees.
Next, let's consider the N-C-O bond angle. The N atom is bonded to the central carbon atom, and the O atom is also bonded to the same carbon atom.
In a linear molecule, the bond angle between any two atoms is also 180 degrees. Therefore, the ideal N-C-O bond angle is 180 degrees.
Finally, let's determine the C-N-C bond angle. In the H3CNCO molecule, the N atom is bonded to the central carbon (C) atom, and another carbon (C) atom is bonded to the nitrogen atom.
Since we have a linear molecule, the C-N-C bond angle is also 180 degrees.
Therefore, the answers to the questions are as follows:
- The ideal H-C-H bond angle is 180 degrees.
- The ideal N-C-O bond angle is 180 degrees.
- The ideal C-N-C bond angle is 180 degrees.