Span of a bridge is 32.0m and has a mass of 5.38x10^4 kg. A truck of mass 11700kg is stopped at 11.4m from one end. Find upwards force that must be exerted by each pair
f1+f2=5.38E4+1.17E4
sum momentums around the truck...
F2*11.4=F1*(32-11.4)
so now, two equations, two unknowns, solve for f1 and f2