A car starts travelling from rest and undergoes constant acceleration for 10 seconds. If it is travelling at 6m/s after 3 seconds what will be its final velocity?
v(3)=a*3=6m/s
a=3m/s^2
v(10)=3*10=30m/s
To find the final velocity of the car, we can use the equation of motion:
v = u + at
Where:
v = final velocity
u = initial velocity (which is 0 since the car starts from rest)
a = acceleration
t = time
Given:
u = 0 m/s (car starts from rest)
a = constant acceleration
t = 10 seconds (total time)
v = ? (final velocity)
We are given that the car reaches a velocity of 6 m/s after 3 seconds. Plugging in the values into the equation:
6 m/s = 0 m/s + a * 3 s
Now, we can solve for the acceleration (a):
a = (6 m/s - 0 m/s) / 3 s
a = 2 m/s^2
Now that we know the acceleration, we can use it along with the total time (t = 10 seconds) to find the final velocity (v):
v = 0 m/s + (2 m/s^2) * 10 s
v = 20 m/s
Therefore, the final velocity of the car after 10 seconds will be 20 m/s.