chemisty help

for the reaction shown, compute the theoretical yield of the product in grams for each of the following initial amounts of reactants.

Ti + 2F2 to make TiF4

There are 3 sub questions for this. Help me out with one, then I'll try to figure out the rest. thanks

a) 4.8g Ti; 3.2gF2

This is a limiting reagent problem. It is worked the same way as a regular stoichiometry problem is worked but with a twist or two.

Step1. Write the balanced equation.
Ti + 2F2 ==> TiF4

Step 2. Convert grams into mols.
3a. mols Ti = grams/atomic mass = 4.8/48 = 0.1 mol Ti

3b. mols F2 = 3.2g/38 = 0.084 mol F2.

Step 3. Using the coefficients in the balanced equation, convert mols in a and b of part 2 to mols of the product.
3a. convert mols Ti.
0.1 mol Ti x (1 mol TiF4/1 mol Ti) = 0.1 x 1/1 = 0.1 mol TiF4 produced.

3b. convert mols F2.
0.084 mol F2 x (1 mol TiF4/2 mols F2) = 0.084 x 1/2 = 0.0421 mol TiF4 produced.

3c. Obviously, both numbers can't be correct. The smaller of the two numbers of mols will be the correct one to use and that is the limiting reagent. Therefore, 0.0421 will be the mols TiF4 produced.

Step 4. Convert mols TiF4 to grams.
grams TiF4 = mols TiF4 x molar mass TiF4.

For a regular stoichiometry problem you won't have steps 2b or 3b or 3c. Everything else is the same.
You will need to go through this problem again because I just estimated the atomic masses of F2 and Ti. Post your work if you get stuck. Check my work. It's easy to make a typo when I'm in a hurry.

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