In the figure below, a wheel of radius 0.275 m is mounted on a frictionless
horizontal axle. A massless cord is wrapped around the wheel and attached to a
1.95 kg box that slides on a frictionless surface inclined at angle θ = 32.7 ° with the
horizontal. The box accelerates down the surface at 2.15 m/s2. Calculate the
rotational inertia of the wheel about the axle.

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  1. mg sinθ = ma + Iα
    where α = a/r
    solve for I

    Although without a diagram I can't be certain

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  2. Don't forget that torque=I(alpha), so multiply mg sin(theta) and ma both by r so you'll be in the same units.

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