I need help with this question, I don't know how to do it.
If 210 mL of isopropyl alcohol is diluted with water to a total volume of 300 mL, what is the percent by volume of isopropyl alcohol in the solution?
volume percent = [(volume solute/total volume solution)]*100 = ?
% v/v = (210/300)*100 = ?
I don't know, is 70% the answer??
Yes, but why don't don't you know? It's just substitute and solve for the answer.
I did I just wanted to make sure that it really was right. Thanks for the help.
To find the percent by volume of isopropyl alcohol in the solution, you need to calculate the ratio between the volume of isopropyl alcohol and the total volume of the solution and then convert it to a percentage.
Here's how you can solve it step by step:
1. Calculate the volume of isopropyl alcohol in the solution:
210 mL (volume of isopropyl alcohol)
2. Calculate the total volume of the solution:
300 mL (total volume after dilution)
3. Find the ratio of the volume of isopropyl alcohol to the total volume of the solution:
Volume of isopropyl alcohol / Total volume of the solution
210 mL / 300 mL
4. Simplify the ratio:
Divide both the numerator and denominator by their greatest common divisor, which is 30 in this case:
210 mL / 30 = 7 mL
300 mL / 30 = 10 mL
5. Convert the ratio to a percentage:
(Volume of isopropyl alcohol / Total volume of the solution) x 100%
(7 mL / 10 mL) x 100%
0.7 x 100%
70%
Therefore, the percent by volume of isopropyl alcohol in the solution is 70%.