calculate the amount of heat released, in joules, in converting 75.0 g of steam at 115 degrees of Celsius to steam at 110 degrees Celcius
q = mass steam x specific heat steam x (Tfinal-Tinitial)
To calculate the amount of heat released in converting 75.0 g of steam at 115 degrees Celsius to steam at 110 degrees Celsius, you need to use the formula:
Q = m * C * ΔT
Where:
Q is the amount of heat released (in joules)
m is the mass of the substance (in grams)
C is the specific heat capacity of the substance (in joules/gram·degree Celsius)
ΔT is the change in temperature (in degrees Celsius)
First, you need to identify the specific heat capacity of water, which is the same as that of steam since they are both forms of H2O. The specific heat capacity of water is approximately 4.18 J/g·°C.
Next, calculate the temperature change (ΔT) by subtracting the final temperature from the initial temperature:
ΔT = final temperature - initial temperature
ΔT = 110°C - 115°C
ΔT = -5°C
Now, plug in the values into the formula:
Q = m * C * ΔT
Q = 75.0 g * 4.18 J/g·°C * (-5°C)
Q = -1567.5 J
The negative sign indicates heat is being released. Therefore, the amount of heat released in converting 75.0 g of steam at 115 degrees Celsius to steam at 110 degrees Celsius is approximately -1567.5 joules.