Write a MIPS assembly language program that displays the binary string of the
content of register $t0.
google is your friend. You might start here:
http://stackoverflow.com/questions/14622371/how-do-i-print-a-binary-number-with-an-inputed-integer
To write a MIPS assembly language program that displays the binary string of the content of register $t0, you can follow these steps:
1. Initialize the $t0 register with the desired value.
2. Create a loop that performs the binary conversion and then displays each bit.
3. Inside the loop, shift the value of $t0 right by one bit using the srl instruction.
4. Use the andi instruction to mask the least significant bit of the $t0 register and load it into another register.
5. Convert the binary value to its ASCII equivalent using the addi instruction (addi $t1, $0, '0' for 0 or addi $t1, $0, '1' for 1).
6. Display the ASCII character using the syscall instruction with code 11.
Here's an example code snippet that demonstrates the steps described above:
```
.data
message: .asciiz "Binary representation:"
.text
main:
# Initialize $t0 with desired value
li $t0, 42
# Display the message
la $a0, message
li $v0, 4
syscall
# Convert and display the binary string
li $t2, 31 # loop counter (31 bits in MIPS)
loop:
srl $t1, $t0, 31 # Get the least significant bit
andi $t1, $t1, 1 # Mask the bit
addi $t1, $t1, '0' # Convert bit to ASCII
# Display the ASCII character
move $a0, $t1
li $v0, 11
syscall
sll $t0, $t0, 1 # Shift $t0 left by 1 bit
sub $t2, $t2, 1 # Decrement loop counter
bgtz $t2, loop # Repeat until all bits are displayed
# Exit the program
li $v0, 10
syscall
```
This code will display the binary string representation of the value stored in register $t0. Note that the code assumes a terminating null character for the message string.