A youth organization collected nickels and dimes for a charity drive. By the end of the 1-day drive, the youth had collected $57.75. If there were five times as many dimes as nickels, how many of each type of coin was collected?

Question

A youth organization collected nickels and dimes for a charity drive. By the end of the 1-day drive, the youth had collected $57.75. If there were five times as many dimes as nickels, how many of each type of coin was collected?

Answer 1

number of nickels --- x

number of dimes ----- 5x

5x + 10(5x) = 5775

solve for x, it is easy

Answer 2

You need to use a system of equations. Lets say that N equals the number of nickels, and D is the number of dimes.

D = 5 x N

because there are 5 times as many dimes as nickels

.05N + .1D = 57.75

the .05 and .1 represent the value of the coins (N is 5 cents, D is 10)

Well, you know the value of D is 5 x N, so you can substitute it into the problem

.05N + .1(5 x N) = 57.75
.05N + .5N = 57.75
.55N = 57.75
N = 105

Now that you know the number of nickels, plug the value back into the first equation to find out the number of dimes

D = 5 x N
D = 5 x 105
D = 525

So the answer is 105 nickels and 525 dimes

Answer 3

Jessica has a handful of nickels and quarters worth a total of $5.455. If she has seven more nickels than quarters, how many of each type of coin does she have?

Answer 4

To solve this problem, we can use a system of equations. Let's represent the number of nickels as 'n' and the number of dimes as 'd'.

From the given information, we can deduce two equations:

1) The total value of nickels and dimes collected is $57.75:
0.05n + 0.10d = 57.75

2) The number of dimes is five times the number of nickels:
d = 5n

Now we can substitute the value of 'd' from equation (2) into equation (1) to find the number of nickels:

0.05n + 0.10(5n) = 57.75

Simplifying the equation:

0.05n + 0.50n = 57.75

Combining like terms:

0.55n = 57.75

To isolate 'n', we divide both sides of the equation by 0.55:

n = 57.75 / 0.55

Evaluating the right side of the equation:

n ≈ 105

So, the number of nickels collected is approximately 105.

Now, we can substitute this value back into equation (2) to find the number of dimes:

d = 5n
d = 5 * 105
d = 525

Therefore, the number of dimes collected is 525.

In conclusion, the youth organization collected 105 nickels and 525 dimes.

A youth organization collected nickels and dimes for a charity drive. By the end of the​ 1-day drive, the youth had collected ​$57.75. If there were five times as many dimes as​ nickels, how many of each type of coin was​ collected?

number of nickels --- x

You need to use a system of equations. Lets say that N equals the number of nickels, and D is the number of dimes.

Jessica has a handful of nickels and quarters worth a total of ​$5.455. If she has seven more nickels than​ quarters, how many of each type of coin does she​ have?

To solve this problem, we can use a system of equations. Let's represent the number of nickels as 'n' and the number of dimes as 'd'.

A youth organization collected nickels and dimes for a charity drive. By the end of the 1-day drive, the youth had collected $57.75. If there were five times as many dimes as nickels, how many of each type of coin was collected?

Jessica has a handful of nickels and quarters worth a total of $5.455. If she has seven more nickels than quarters, how many of each type of coin does she have?