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Hi, can someone give me the answer to this question: secAtanA=1/4. Find cosA I got: CosA=4(1sinA) Is my answer good? Now multply each side by (1+sinA) CosA(1+sinA)=4 cos^2 A CosA=1/4 (1+sinA) 16(1sinA)=1+sinA 15=17SinA So you
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prove that sinAcosA+1/sinA+cosA1=1/secAtanA
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I need to count this: a) 1tg^2a/1+ctg^2a, when sina =2/3 b) 1tg^2a/1ctg^2a, when cosa= 1/3 c) tga * cos^2a, when sina + cosa=5/7 d) tg^2a + 1/sina * 1/cosa + ctg^2a, when tga + ctga =5
asked by Evelina on November 30, 2011